The zip function combines two lists into tuples. If the lists are of differing lengths, the shorter length is used. If you don’t like this behavior, the zipAll function will keep all elements, filling in specified values for the blanks (compare this to the recycling rule in R, which lets you continuously cycle through the shorter list).<\/p>\n
\nval arr1 = List(\"a\", \"b\", \"c\")\nval arr2 = List(1, 2, 3)\n\narr1.zip(arr2)\n<\/pre>\nThe result is tuples of each:<\/p>\n
\nres2: List[(String, Int)] = List((a,1), (b,2), (c,3))\n<\/pre>\nIf you make a longer array, you get tuples with a length at the shortest of the two:<\/p>\n
\nvar arr3 = List(4, 5, 6, 7)\narr1.zip(arr3)\n<\/pre>\n\nres3: List[(String, Int)] = List((a,4), (b,5), (c,6))\n<\/pre>\nThis also applies if you use a shorter array:<\/p>\n
\nvar arr4 = List(4, 5)\narr1.zip(arr4)\n<\/pre>\nResult:<\/p>\n
\nres5: List[(String, Int)] = List((a,4), (b,5))\n<\/pre>\nIf you don’t like this behavior, consider using zipAll<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"The zip function combines two lists into tuples. If the lists are of differing lengths, the shorter length is used. If you don’t like this behavior, the zipAll function will keep all elements, filling in specified values for the blanks (compare this to the recycling rule in R, which lets you continuously cycle through the … <\/p>\n