The “sortWith” function lets you sort an array according to a specified rule.<\/p>\n
To demonstrate this, let’s make a list of random numbers:<\/p>\n
\nval x = \n List.fill(20)(100)\n .map(scala.util.Random.nextInt)\n\nx: List[Int] = \n List(90, 13, 69, 46, 66, \n 86, 38, 18, 88, 26, \n 81, 18, 11, 74, 5, \n 50, 7, 42, 74, 57)\n<\/pre>\nYou can sort this like so:<\/p>\n
\nx.sortWith(\n (a, b) => {\n a > b\n }\n)\n<\/pre>\nNote that you should never use “return” in scala. <\/p>\n
The above code can be re-written more simply:<\/p>\n
\nx.sortWith(\n (a, b) =>\n a > b\n)\n<\/pre>\nHowever, “a”, and “b” have no importance here. For simple implementations, you can use an underscore syntax, <\/p>\n
\nx.sortWith(_ > _)\n<\/pre>\nWhat this does is to create a comparison function that takes two arguments, and checks if the first is larger than the second – in this case the “_” is not a variable, but more of a placeholder syntax.<\/p>\n","protected":false},"excerpt":{"rendered":"
The “sortWith” function lets you sort an array according to a specified rule. To demonstrate this, let’s make a list of random numbers: val x = List.fill(20)(100) .map(scala.util.Random.nextInt) x: List[Int] = List(90, 13, 69, 46, 66, 86, 38, 18, 88, 26, 81, 18, 11, 74, 5, 50, 7, 42, 74, 57) You can sort this … <\/p>\n